If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4b+6b^2-10=0
a = 6; b = 4; c = -10;
Δ = b2-4ac
Δ = 42-4·6·(-10)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*6}=\frac{-20}{12} =-1+2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*6}=\frac{12}{12} =1 $
| 7x-15=9+4x | | -8r(r-3r)-4(r-1)=0 | | 36p+18=-27 | | 540=x-30+x-30+x-30+x+x | | |x-5|+4=9 | | 99=5x+24 | | 3^2x=27^x+1 | | 36p+18=27 | | X-4+2x-5=180 | | 8x-9+3x+1=7x+14 | | 6b^2+4b-10=0 | | 6-2k+1=15 | | 8x–11(x–2)=-8 | | 17z=16z+16 | | 10-f=2 | | (11x−25)+(24x+10)=90 | | 12-4yy=-3 | | 3n/4=-18/5 | | -(x-6)-3=4(2x+8) | | -13-19f=-2f+14-20f | | 11y+2=-31 | | 40=10c-2 | | 4x-6-x+6=x | | -3=12y+5(7-2y) | | 3x/3+6=-2.3 | | 2(5x-8)=79-20 | | 3−2(9+2m)=m | | 5(x+6)+11=9x-4(x-3) | | 9|4p+2|+8=35 | | 28=x/2+5 | | 5d+10-3d=2(5+d) | | x-37=51 |